Question

A force acts for $10s$ on a stationary body of mass $100kg$ after which the force ceases to act. The body moves through a distance of $100m$ in the next $5s$. Calculate the velocity.

Answer 1

Let initial velocity = u = 0

Using equation of motion, v = u +at = 0+a(10) = 10a

distance in 10 sec = s = vt = $100=10a\left(5\right)$

$a=2m/s^2$

$\therefore v=10a=10\left(2\right)m/s=20m/s$