Question

A force acts for 5 second on a body of mass 10 kg. After it ceases to act, the body describe 5 m in the next 5 second. Find the magnitude of the force.

Answer 1

Using second equation of motion we can find the acceleration

$\Rightarrow s=ut+\frac{1}{2}a{t}^2$

$\Rightarrow 5=0\left(5\right)+\frac{1}{2}a{5}^2$

$\Rightarrow a=\frac{2}{5}m/s^2$

And hence, $F=ma=\frac{2}{5}\times 10=4N$