The correct option is B 384 J
Given: mass of body, m=12 kg, acceleration produced by force, a=2 ms−2, initial velocity, u=0 (body initially at rest), final velocity, v=8 ms−1.
Let the work done by force of magnitude F be W.
Initial kinetic energy of the body: =12mv2=0 (As the body is initially at rest)
Final kinetic energy of the body: =12mv2
⇒12×12×82=384 J
Now, work done = change in kinetic energy
i.e, work done = final K.E - initial K.E
⇒(384−0) J=384 J
Therefore, the work done by the force is 384 J