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Question

A force causes a stationary body of mass 12 kg to be accelerated at a rate of 2 ms−2 . If the final velocity of the body is 8 ms−1, find the work done by the force.

A
360 J
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B
384 J
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C
396 J
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D
420 J
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Solution

The correct option is B 384 J
Given: mass of body, m=12 kg, acceleration produced by force, a=2 ms2, initial velocity, u=0 (body initially at rest), final velocity, v=8 ms1.
Let the work done by force of magnitude F be W.

Initial kinetic energy of the body: =12mv2=0 (As the body is initially at rest)
Final kinetic energy of the body: =12mv2
12×12×82=384 J

Now, work done = change in kinetic energy
i.e, work done = final K.E - initial K.E
(3840) J=384 J
Therefore, the work done by the force is 384 J

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