wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A force exerts an impulse I on a particle changing its velocity from initial velocity u m/s to final velocity 2u m/s. If the applied force and initial velocity are oppositely oriented along the same line, find the work done by force.

A
12|I|u
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
32|I|u
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
13|I|u
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2|I|u
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 12|I|u

Taking rightward motion as + ve.
Impulse, I= change in momentum Δp
I=m(vfinalvinitial)
=m(2uu)
=3mu
|I|=3mu ...(i)

Let work done by impulsive force is W.
From work energy theorem,
W=ΔK.E
=K.EfinalK.Einitial=12mv2final12mv2initial=12m(v2finalv2initial)
=12m((2u)2u2)=32mu2
W=32mu2 ...(ii)
From equation (i) and (ii)
W=12|I|u

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon