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SHM expression

A force F1 ...

Question

A force $F_{1}$ on a body of 2 kg produces an acceleration of $2.5 m / m^{2}$ and other force $F_{2}$ acting on another body of mass 5 kg produces an acceleration of $2 m / s^{2}$ . The ratio of $F_{2} / F_{1}$ is

2

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4

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6

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Solution

The correct option is A $2$
Given,
$m_{1} = 2 k g$
$a_{1} = 2.5 m / s^{2}$
$m_{2} = 5 k g$
$a_{2} = 2 m / s^{2}$

Ratio, $\frac{F_{2}}{F_{1}} = \frac{m_{2} a_{2}}{m_{1} a_{1}}$

$\frac{F_{2}}{F_{1}} = \frac{5 \times 2}{2 \times 2.5} = 2$
The correct option is A.

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Similar questions

F_{1} = F_{2} = F_{3} = F

F

m

a

F_{1} = F_{2} = F_{3} = F

4 m / s^{2}

m_{1}

6 m s^{- 2}

m_{2}

m_{1} + m_{2}

5 k g

F_{1} = 10 N

F_{2} = 10 N

F_{3} = 10 \sqrt{2} N

N - W

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