A force F - 5 i - 3 j - 2 k- moves a particle from r1 - 2 i - 7 j - 4 k- to r 2 - 5 - - 2 - - 8 k- Calculate the workdone-

The correct option is A 38 units [ r⃗ =3î 5ĵ +4k̂ =( r⃗ #160; _ 2 r⃗ #160; _ 1 ) #160;; ...

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A force F =...

Question

A force $F = 5 i - 3 j + 2^k$ moves a particle from $r_{1} = 2 i + 7 j + 4^k$ to $r_{2} = 5^i + 2^j + 8^k \cdot$ Calculate the workdone:

38 units

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30 units

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20 units

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15 units

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Solution

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\to F = 5^i - 3^j + 2^k

_{1} = 2^i + 7^j + 4^k

_{2} = 5^i + 2^j + 8^k

\to F = (^i + 2^j + 3^k) N

r_{1} = (^i +^j +^k)

r_{2} = (^i -^j + 2^k)

\to F = (^i + 2^j + 3^k) N

r_{1} = (^i +^j +^k)

r_{2} = (^i -^j + 2^k)

{\to r}_{1} = 3^i + 2^j - 6^k

{\to r}_{2} = 14^i + 13^j - 9^k

(4^i +^j + 3^k)

N

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