Question

A force $F$ acting on an object varies with distance $x$ as shown in the figure. The force is in $N$ and $x$ in $m$. The work done by the force in moving the object from $x=0$ to $x=6m$ is:

• A. 13.5 J
• B. 10 J
• C. 15 J
• D. 20 J

Answer 1

The correct option is A 13.5 J

Work done in moving the object by distance $x={\int }_0^{x}F.dx$

$=$ Area under the given curve [from $x=0m$ to $x=6m$]

$=(3\times 3)+(\frac{1}{2}\times 3\times 3)$

$=13.5J$