A force F is applied horizontally on mass m1 as shown in figure. Find the contact force between m1 and m2.
A
m2Fm1+m2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
m1Fm1+m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
m1F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
m2F
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Am2Fm1+m2 Considering both blocks as a system to find the common acceleration.
Common acceleration a=F(m1+m2)……(1)
To find the contact force between A and B we draw F.B.D. of mass m2. ∑Fx=max N=m2.a N=m2F(m1+m2)