Question

A force of $10N$ displaces a body by $5m$, the angle between force and displacement is ${60}^o$, then find the work done.

Answer 1

Step 1: Given data:

Force, $F=10N$

Displacement, $s=5m$

Angle made by applied force in the horizontal direction, $\theta ={60}^o$

Step 2: Find the work done:

$$\begin{gathered} W=Fscos\theta \\ =10\times 5\times cos{60}^{\mathrm{o}} \\ =10\times 5\times \frac{1}{2} \\ =25J \end{gathered}$$

Hence, the work done is $\mathbf{25}\mathbf{}\mathit{J}\mathit{o}\mathit{u}\mathit{l}\mathit{e}$.