Question

A force of $10N$ displaces a body by a distance of $2m$ at an angle of ${60}^0$ to its own direction. What is the amount of work done?

• A. $1J$
• B. $10J$
• C. $100J$
• D. $1kJ$

Answer 1

Answer: (B)

$10J$

$F=10N,S=2m,\theta ={60}^0$

So, $Work=F\times Scos\theta =10\times 2cos{60}^0$
$=10\times 2\times \frac{1}{2}=10J$