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Standard XII

Physics

1st Equation of Motion

A force of 20...

Question

A force of 20 N on a 3 kg box is applied to overcome a frictional force of 5 N and accelerate the box. Calculate the acceleration of the box?

m / s^{2}

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m / s^{2}

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m / s^{2}

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m / s^{2}

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m / s^{2}

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Solution

The correct option is B 5 $m / s^{2}$
Given : $m = 3 k g$ $F = 20$ N
Frictional force $f = 5$ N
Thus acceleration of the box $a = \frac{F - f}{m} = \frac{20 - 5}{3} = 5$ $m / s^{2}$

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A force of 20 N on a 3 kg box is applied to overcome a frictional force of 5 N and accelerate the box. Calculate the acceleration of the box?

The correct option is B 5 m/s2Given : m=3kg F=20 NFrictional force f=5 NThus acceleration of the box a=F−fm=20−53=5 m/s2

The correct option is B 5 $m / s^{2}$
Given : $m = 3 k g$ $F = 20$ N
Frictional force $f = 5$ N
Thus acceleration of the box $a = \frac{F - f}{m} = \frac{20 - 5}{3} = 5$ $m / s^{2}$