A force of $50 N$ is applied on a body of mass $2 k g$ at an angle of 30° with the vertical. Find the acceleration with which the body moves in the horizontal direction.

11.5

m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12.5

m / s^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

13.5

m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14.5

m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 12.5 $m / s^{2}$

Horizontal component of force $= F cos (θ)$
where $θ$ is the angle between the force and horizontal direction.
$F r o m s e c o n d l a w, F cos (θ) = m a a = \frac{F cos (60)}{m} a = \frac{50 cos (60)}{2} = 12.5 m / s^{2}$

Suggest Corrections

Similar questions

Q. A force of

50 N

is inclined to the vertical at an angle of

30^{o}

. Find the acceleration it produces in a body of mass

2 k g

which moves in the horizontal direction.

A force of $50 N$ is applied on a body of mass $2 k g$ at an angle of 30° with the vertical. Find the acceleration with which the body moves in the horizontal direction.

Q. A pulley mass arrangement is shown is the figure. A force of

50 N

is applied on the

2 kg

block. Find the acceleration of COM of the system.

A force of 20 N is applied on a body of mass 4 kg kept on a rough surface having coefficient of friction 0.1. Find acceleration of body. Take g = 10 m/s²

Q. A force of

10 N

inclined to the horizontal at an angle of

60^{o}

acts on a body of mass

2 K g

. If the body can move in horizontal direction only find its acceleration.

Join BYJU'S Learning Program

A force of 50 N is applied on a body of mass 2 kg at an angle of 30° with the vertical. Find the acceleration with which the body moves in the horizontal direction.

The correct option is B 12.5 m/s2 Horizontal component of force=Fcos(θ) where θ is the angle between the force and horizontal direction. From second law, Fcos(θ)=ma a=Fcos(60)ma=50cos(60)2=12.5 m/s2

A force of $50 N$ is applied on a body of mass $2 k g$ at an angle of 30° with the vertical. Find the acceleration with which the body moves in the horizontal direction.

The correct option is B 12.5 $m / s^{2}$

Horizontal component of force $= F cos (θ)$
where $θ$ is the angle between the force and horizontal direction.
$F r o m s e c o n d l a w, F cos (θ) = m a a = \frac{F cos (60)}{m} a = \frac{50 cos (60)}{2} = 12.5 m / s^{2}$