A force of $500 d y n e$ acts on an object where the object moves through $8 m$ in the direction of force. Calcualate the work done in this case

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Solution

$F = 500 d y n e = 500 \times 10^{- 5} = 0.005 N$
$s = 8 m$
$W o r k d o n e = F o r c e \times D i s t a n c e$
$W = 0.005 \times 8$
$W = 0.04 J$

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A force of 500 dyne acts on an object where the object moves through 8 m in the direction of force. Calcualate the work done in this case

F=500 dyne=500×10−5=0.005Ns=8mWorkdone=Force×DistanceW=0.005×8W=0.04J

A force of $500 d y n e$ acts on an object where the object moves through $8 m$ in the direction of force. Calcualate the work done in this case

$F = 500 d y n e = 500 \times 10^{- 5} = 0.005 N$
$s = 8 m$
$W o r k d o n e = F o r c e \times D i s t a n c e$
$W = 0.005 \times 8$
$W = 0.04 J$