A force of $525 N$ produces a moment of force of $420 N m$ . Calculate the shortest distance between the point of application of force and the turning point.

2.8 m

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0.8 m

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1.8 m

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0.4 m

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Solution

The correct option is B $0.8 m$
Force $F = 525 N$
Moment of force $τ = 420 N m$
Shortest distance between the point of application of force and turning point $r = \frac{τ}{F}$
$⟹ r = \frac{420}{525} = 0.8 m$

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