A force of 60 N acts on a body that moves it through a distance of 4m on a horizontal surface. What is the work done, if the direction of force is at an angle of 60° to the horizontal surface?
120J
Work done:
Where F= force applied
S = Displacement covered
x = Angle between force and displacement
Given data:
Force applied F = 60N
Distance covered = 4m
The angle between them = 60°
Applying this to the given data:
Hence option b is the correct answer