Question

A force of $7\mathrm{N}$ acts on an object. The displacement is say $8\mathrm{m}$ in the direction of the force. Let us take it that the force acts on the object through the displacement. What is the work done in this case?

Answer 1

Step 1: Given data

Force acting on an object, $\mathrm{F}=7N$

Displacement in the direction of force, $\mathrm{S}=8m$ $(\cos \theta =1=\theta =0^o)$

Step 2: Calculate the work done

Work done $\mathrm{W}$ is calculated below:

$$\begin{gathered} \mathrm{W}=\mathrm{F}\times \mathrm{S} \\ \mathrm{W}=7N\times 8m \\ \mathrm{W}\mathit{=}\mathit{56}\mathit{}J \end{gathered}$$

Hence, the work done is $\mathit{56}\mathit{}J$.