Question

A force of $7N$ acts on an object. The displacement is, say $8m$, in the direction of the force. Let us take it that the force acts on the object through the displacement. What is the work done in this case?

Answer 1

Step 1: Given data

Force acting on the body (F) = $7N$

Displacement of the body (S) = $8m$

Step 2: Formula used

$W=FS\cos \theta$, where W is the work done, F is the force acting on the body, S is its displacement and $\theta$ is the angle between the direction of force and the displacement vector.

Step 3: Calculate work done

Since the body is displaced in the direction of the applied force, $\theta =0$.

Now, on substituting the given values in the formula, we get:

$$\begin{gathered} W=7·8·\cos (0°) \\ W=7·8·1 \\ W=56J \end{gathered}$$

Thus, the work done in this case will be $56J$.