A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force acts on the object through the displacement. What is the work done in this case? [2 MARKS]

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Solution

Each point: 1 Mark

1. When a force F acts on an object to displace it through a distance S in its direction, then the work done
W on the body by the force is given by:
Work done = $F o r c e \times D i s p l a c e m e n t$
$W = F \times S$

2. Where, F = 7 N S = 8 m
Therefore, work done,
$W = 7 \times 8$ = 56 Nm = 56 J

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A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force acts on the object through the displacement. What is the work done in this case? [2 MARKS]

Each point: 1 Mark 1. When a force F acts on an object to displace it through a distance S in its direction, then the work done W on the body by the force is given by: Work done = Force×Displacement W=F×S 2. Where, F = 7 N S = 8 m Therefore, work done, W=7×8 = 56 Nm = 56 J