A force →F=(5^i+3^j2^k)N is applied over a partivle which displaces it from its origin to the point →r=(2^i−^j)m. The work done on the particle in joules is then
A
−7
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B
+7
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C
+10
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D
+13
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Solution
The correct option is B+7 W=→F.Δ→r=(5^i+3^j2^k).(2^i−^j)=10−3=7Joule