A force produces an acceleration of $5 m / s^{2}$ . When it acts on the body of mass $30 g .$ Find the force in newtons.

Open in App

Solution

Step 1: Given data
The acceleration of the body $a = 5 m / s^{2}$
The mass of the body $(m) = 30 g = 0.03 k g (\sin c e 1000 g = 1 k g)$
Step 2: using Newton's second law we get-
$F = m a F = F o r c e m = m a s s a = a c c e l e r a t i o n$
Step 3: Calculate the force by substituting the value of mass and acceleration.
$F = (0.03) \times (5) F = 0.15 N$
Hence, the force applied to the body is $0.15 N$

Suggest Corrections

Similar questions

5.0 c m s^{- 2}

A force produces an acceleration of $5.0 c m / s^{2}$ when it acts on a body of mass 20 g. The force in newton is:

A force produces an acceleration of $5 \frac{c m}{s^{2}}$ . When it acts on a body of $20 g$ . Then the force in newtons is:

5 m / s^{2}

18 m / s^{2}

g = 10 m / s^{2}

s^{- 2}

Join BYJU'S Learning Program