A force →F=(5^i+3^j) N is applied on a particle which displaces it to the point →r=(2^i−^j) m from the origin. The work done on the particle is
A
-7 J
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B
+13 J
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C
+7 J
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D
11 J
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Solution
The correct option is C +7 J Given →F=5^i+3^j →r=2^i−^j The work done on the particle is a scalar product of F and r, hence W=F.r W=(5^i+3^j).(2^i−^j) W=10−3=+7J