Question

A free falling body travels ___ of total distance in 5th second.

• A. 8 %
• B. 12 %
• C. 25 %
• D. 36 %

Answer 1

The correct option is D 36 %

The correct option is D

Given,

A free falling body

Distance traveled in 5s

$S=ut+\frac{1}{2}g{t}^2$ since $u=0,g=10m/s$

$=\frac{1}{2}\times 10\times 5^2$

$=125m$

Distance travelled in 5^th sis:

Distance travelled in 5s- Distance travelled in 4s

Distance travelled in $4s=\frac{1}{2}\times 10\times 4^2$

$=80m$

So,

$s_5-s_4=125-80=45$

Therefore,

$\frac{s_5-s_4}{s_5}\times 100=\frac{45}{125}\times 100=36\%$