A free neutron has half life of $14$ minutes. Its decay constant is :

8.25 \times 10^{- 5} S^{- 1}

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8.25 \times 10^{- 2} S^{- 1}

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8.25 \times 10^{- 4} S^{- 1}

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8.25 \times 10^{1} S^{- 1}

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Solution

The correct option is C $8.25 \times 10^{- 4} S^{- 1}$
The decay constant is given as,

$λ = \frac{0.693}{t_{\frac{1}{2}}}$

$= \frac{0.693}{14 \times 60}$
$= 8.25 \times 10^{- 4} s^{- 1}$

Thus, the decay constant of the free neutron is $8.25 \times 10^{- 4} s^{- 1}$ .

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A free neutron has half life of 14 minutes. Its decay constant is :

The correct option is C 8.25×10−4S−1The decay constant is given as,λ=0.693t12=0.69314×60=8.25×10−4s−1 Thus, the decay constant of the free neutron is 8.25×10−4s−1.

A free neutron has half life of $14$ minutes. Its decay constant is :

The correct option is C $8.25 \times 10^{- 4} S^{- 1}$
The decay constant is given as,

$λ = \frac{0.693}{t_{\frac{1}{2}}}$

$= \frac{0.693}{14 \times 60}$
$= 8.25 \times 10^{- 4} s^{- 1}$

Thus, the decay constant of the free neutron is $8.25 \times 10^{- 4} s^{- 1}$ .