Question

A frisbee disc has a diameter of 26 inches. Find the distance covered by the disc in 3 revolutions.
(Take value of π = 22/7)

Answer 1

$\text{Diameter of the disc,}d=26\text{inches}$
$\text{Radius of the disc,}r=26÷2=13\text{inches}$

$\begin{array}{cc}\text{Distance covered by the disc}& =\text{No. of revolution}\times \text{Perimeter of the disc}\\ & =3\times 2\pi r\\ & =3\times 2\times \frac{22}{7}\times 13\\ & =245.14\end{array}$

Therefore, the distance covered by the disc is $245.14\text{inches}$.