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Question

# A fruit retail merchant buys two types of oranges, one at the rate of 20 per 100 rupees and the same number of the other type at the rate of 25 per 100 rupees. He mixed these two types of oranges and sold them at the rate of 18 per 100 rupees. Find the total number of oranges he bought of each type if he made a gain of Rs. 342 from the business.

A
342
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B
324
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C
171
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D
162
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Solution

## The correct option is D 162Cost price of type I orange =10020= Rs. 5/orange Cost price of type II orange =10025= Rs. 4/orange Average price when both these types are mixed (equal quantity) =(4+5)2=Rs.4.5 Selling price of an orange =10018=Rs.559 Profit made per orange =559−4.5=Rs.1118 Number of oranges sold = Number of oranges bought =3421118=324 So, he bought 3242=162 oranges of each type. Alternate method: Let us assume that he bought xoranges of each type. Total number of oranges bought/sold = 2x Profit = Total SP - Total CP (10018×2x)−((5×x)+(4×x)]= Rs. 342=>x(20018−(4+5))=342=>x=3428×18 = 162

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