Question

A shopkeeper bought oranges at the rate of $7$ for $10$ rupees and sold them at a profit of $40$ per cent. How many oranges would he sells for $10$ rupees?

• A. $9$
• B. $5$
• C. $6$
• D. $4$

Answer 1

Answer: (B)

$5$

Let's solve the problem on saved quantity( not on price).

$\frac{savedquantity}{soldquantity}=40\%$

$⟹\frac{x}{(7-x)}=0.4$

$⟹x=2$

Hence he saved $2$ oranges and sold $5$ oranges in $10$ rupee.

$ALTERNATE:-$

Let us assume person buy $7$ orange

His cost of $7$ orange $=10$

As he wants $40\%$ profit ,

His selling price for $7$ orange will be $=10+40\%of10=14$

Selling price of one orange $=\frac{14}{7}=2$

In $10$ rupee number of orange he will sell $=\frac{10}{2}=5$