Question

A fruit seller loses 10% by selling oranges at 26 for Rs. 25. How many oranges should he sell for Rs. 5 to gain 17 per cent ?

Answer 1

Given, Selling price of $26$ oranges $=Rs25$
=> Selling price of $1$ orange $=Rs\frac{25}{26}$

Now, Loss on $26$ oranges % $=10$ %
$=>\frac{C.P.-S.P.}{C.P.}\times 100=10$
$=>\frac{C.P.-25}{C.P.}\times 100=10$
$=>C.P.-25=0.1C.P.$
$=>0.9C.P.=25$
$=>C.P.$ of $26$ oranges $==\frac{250}{9}$

Hence, Cost price of $1$ orange $=Rs\frac{250}{234}=Rs\frac{125}{117}$

Now,

Hence, required Profit % $=\frac{S.P.-C.P.}{C.P.}\times 100=17$
Since $SP2=Rs5$ , we have corresponding CP 2 as :
$\frac{5-CP2}{CP2}\times 100=17$
$=>5-CP2=0.17C.P.2$
$=>1.17C.P.2=5$
$=>C.P.2=Rs\frac{5}{1.17}$

Since, Cost price of $1$ orange $=Rs\frac{125}{117}$
For $Rs\frac{5}{1.17}$, number of oranges $=\frac{\frac{5}{1.17}}{\frac{125}{117}}=4$

So, $4$ oranges need to be sold at $Rs5$