A function f is defined by f(x) = 2x – 5. Write down the values of

(i) f(0), (ii) f(7), (iii) f(–3)

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Solution

The given function is f(x) = 2x – 5.

Therefore,

(i) f(0) = 2 × 0 – 5 = 0 – 5 = –5

(ii) f(7) = 2 × 7 – 5 = 14 – 5 = 9

(iii) f(–3) = 2 × (–3) – 5 = – 6 – 5 = –11

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Similar questions

A function f is defined by f(x) = 2x - 5. Write down the values of:

(i) f(0) (ii) f(7) (iii) f(-3)

f : [- 7, 6) \to R

f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} x^{2} + 2 x + 1; & - 7 \leq x < - 5 x + 5; & - 5 \leq x \leq 2 x - 1; & 2 < x < 6 \end{matrix}

2 f (- 4) + 3 f (2)

f (- 7) - f (- 3)

\frac{4 f (- 3) + 2 f (4)}{f (- 6) - 3 f (1)}

f

f (x) = {\begin{matrix} 2 x + 4, x \leq 2 2 x - 1, x > 2 \end{matrix}

f (0) + f (2) + f (4)

{\frac{- 3}{5}} \to R

\frac{2 x}{5 x + 3}

f^{- 1}

Let $f : R \to R$ be the function defined by $f (x) = 2 x - 3, \forall x \in R$ . Write $f^{- 1}$ .

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