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Question

A function f(x) is even if for all a x, f(x)=f(x), and odd if for all x, f(x)=f(x).

If f(x)=5x6+6x2+7, which of the following is correct?

A
[f(x)] is not even
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B
f(x) is odd
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C
[f(x)] is not odd
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D
f(x) is even
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Solution

The correct option is C f(x) is even
Given, f(x)=5x6+6x2+7

Therefore, f(x)=5(x)6+6(x)2+7

f(x)=5x6+6x2+7

f(x)=f(x)

So f(x) is an even function.

Option D is correct.

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