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Question

A function f(x) satisfies the relation x2f(t)=x22+2xt2f(t)dt
Then answer the following
The range of f(x) is

A
[0,]
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B
R
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C
[12,12]
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D
[12,]
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Solution

The correct option is C [12,12]
x2f(t)dt=x22+2xt2f(t)dtDiff. Wrt xf(x)=xx2f(x)f(x)=x1+x2
Let y=x1+x214y20yϵ[12,12]

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