A function is given as $y = 5 x^{2} - 10 x$ , then

Maximum value of y is 10

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Minimum value of y is -5

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Maximum value of y is 0

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Maximum value of y occurs at x = 1

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Solution

The correct option is B Minimum value of y is -5
By maxima or minima $\Rightarrow \frac{d y}{d x} = 0$
$\Rightarrow 10 x - 10 = 0 \Rightarrow x = 1$
At $x = 1, \frac{d^{2} y}{d x^{2}} = 10$ which is positive.
$∴ A t x = 1,$ there is a minima.
$y_{m i n} = y (1) = 5 - 10 = - 5$ .

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