Question

${}^{\prime }{a}^{\prime }gKH{C}_2{O}_4$ required to reduce $100mL$ of $0.02MKMn{O}_4$ in acid medium and ${}^{\prime }{b}^{\prime }gKH{C}_2{O}_4$ neutralises $100mL$ of $0.05MCa(OH{)}_2$ then:

• A. $a=b$
• B. $2a=b$
• C. $a=2b$
• D. none of the above

Answer 1

The correct option is A $a=b$

We know $KMn{O}_4$ have $n=5$ has its $n$ factor in acidic medium so results are

$100ml$ of $0.02\times 5=0.1N$ $KMn{O}_4$

And $n$ factor for calcium hydroxide is $n=2$.

So, we resulted as

$100ml$ of $0.05\times 2=0.1N$ of $Ca(OH{)}_2$

$\therefore$ So, as both have same volume of solution with same normality inspite of the type of chemical same amount of $KH{C}_2{O}_4$ is required.

$\therefore a=b$