Question

$A$ g of a metal displaces $V$ mL of $H_2$ at NTP. Equivalent mass, $E$ of the metal is :

• A. $E=\frac{A}{massof{H}_{2}displaced}\times E_H$
• B. $E=\frac{A\times 1.008\times 22400}{volumeof{H}_{2}displaced\times 2}$
• C. $E=\frac{A\times 1.008}{volumeof{H}_{2}displaced\times 0.0000897}$
• D. all of the above

Answer 1

The correct option is D all of the above

Equivalent weight is the mass which displaces $11.2$ L of $H_2$ in volume.
So, equivalent mass of element $=\frac{A\times 11200}{V}$ g.