Question

# A(g)→2B(g)+C(g) Initially at t = 0 gas A was present along with some amount of gas C. At At t = 0, the mole fraction of gas C is 13. After some time t=t1, the total pressure is half of the final total pressure at t=tx (a very long time). Assume this decomposition to follow first order kinetics (at a constant temperature). It is also given at t=tx, the final total pressure is 35 bar. At t=t1 pressure of gas B is.

A
2.5 bar
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B
1.25 bar
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C
5.0 bar
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D
Data is insufficient
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Solution

## The correct option is A 2.5 barA(g)→2B(g)+C(g) 23Pi 0 13Pi at t=0 23Pi−p 2p 13Pi+p at t1 23Pi−px 2px 13Pi+px at tx Pi+2p=352 Pi+2px=35 after a very long time 23Pi−px=0 by solving we get Pi=15 2p=2.5 pressure of B at time t is 2.5 bar

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