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Byju's Answer

Standard XII

Chemistry

Factors Affecting Rate of Reaction

A g → 2 B g +...

Question

$A (g) \to 2 B (g) + C (g)$
Initially at t = 0 gas A was present along with some amount of gas C. At At t = 0, the mole fraction of gas C is $\frac{1}{3}$ . After some time $t = t_{1}$ , the total pressure is half of the final total pressure at $t = t_{x}$ (a very long time). Assume this decomposition to follow first order kinetics (at a constant temperature). It is also given at $t = t_{x}$ , the final total pressure is 35 bar.

Ratio of rate constant at t = 0 to $t = t_{1}$ to $t = t_{x}$ is:

2 : 3 : 4

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1 : 1 : 1

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1 : 3 : 5

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1 : 3 : 5

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Solution

The correct option is B 1 : 1 : 1
$k = A e^{\frac{- E_{a}}{R T}}$
rate constant does not depend on concentration of reactant or product.
thus ratio of rate constant is $1 : 1 : 1$

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Similar questions

A (g) \to 2 B (g) + C (g)

Initially at t = 0 gas A was present along with some amount of gas C. At At t = 0, the mole fraction of gas C is

\frac{1}{3}

. After some time

t = t_{1}

, the total pressure is half of the final total pressure at

t = t_{x}

(a very long time). Assume this decomposition to follow first order kinetics (at a constant temperature). It is also given at

t = t_{x}

, the final total pressure is 35 bar.

Ratio of rate constant at t = 0 to

t = t_{1}

t = t_{x}

is:

A (g) \to 2 B (g) + C (g)

Initially at t = 0 gas A was present along with some amount of gas C. At At t = 0, the mole fraction of gas C is

\frac{1}{3}

. After some time

t = t_{1}

, the total pressure is half of the final total pressure at

t = t_{x}

(a very long time). Assume this decomposition to follow first order kinetics (at a constant temperature). It is also given at

t = t_{x}

, the final total pressure is 35 bar.

Rate constant

(k) = (log 64 - log 49) s^{- 1}

. Value of

t_{1}

in seconds is:

A (g) \to 2 B (g) + C (g)

Initially at t = 0 gas A was present along with some amount of gas C. At At t = 0, the mole fraction of gas C is

\frac{1}{3}

. After some time

t = t_{1}

, the total pressure is half of the final total pressure at

t = t_{x}

(a very long time). Assume this decomposition to follow first order kinetics (at a constant temperature). It is also given at

t = t_{x}

, the final total pressure is 35 bar.

Rate constant

(k) = (log 64 - log 49) s^{- 1}

. Value of

t_{1}

in seconds is:

A (g) \to 2 B (g) + C (g)

Initially at t = 0 gas A was present along with some amount of gas C. At At t = 0, the mole fraction of gas C is

\frac{1}{3}

. After some time

t = t_{1}

, the total pressure is half of the final total pressure at

t = t_{x}

(a very long time). Assume this decomposition to follow first order kinetics (at a constant temperature). It is also given at

t = t_{x}

, the final total pressure is 35 bar.

At

t = t_{1}

pressure of gas B is.

Q. When one mole of a monoatomic ideal gas at T K undergoes adiabatic change under constant external pressure of 1atm changes from 1L to 2L volume. The final temperature of the gas in Kelvin is

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The correct option is B 1 : 1 : 1k=Ae−EaRT rate constant does not depend on concentration of reactant or product. thus ratio of rate constant is 1:1:1

The correct option is B 1 : 1 : 1
$k = A e^{\frac{- E_{a}}{R T}}$
rate constant does not depend on concentration of reactant or product.
thus ratio of rate constant is $1 : 1 : 1$