Question

A galvanometer has a resistance $50\Omega$ and is shunted by a $0.5\Omega$ resistor. The fraction of main current that flows through the galvanometer is-

• A. $\frac{1}{10}$
• B. $\frac{1}{11}$
• C. $\frac{1}{101}$
  
• D. $\frac{1}{110}$

Answer 1

The correct option is C $\frac{1}{101}$


Given, $G=50\Omega ;S=0.5\Omega$


As we can see,

$V=I_{g}G=I_{s}S$

$\frac{I_s}{I_g}$ = $\frac{G}{S}$

Now, $\frac{I}{I_g}=\frac{I_g+I_s}{I_g}=\frac{G+S}{S}$ = $\frac{50.5}{0.5}$

$\Rightarrow \frac{I_g}{I}$= $\frac{5}{505}$ = $\frac{1}{101}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(C\right)$ is the correct answer.