A galvanometer has a resistance of 3663 $ω$ . A shunt S is connected across it such that 1/34 of the total current passes through the galvanometer, the external resistance that must be connected in series with the main circuit so that the total current in the main circuit remains unaltered even when the galvanometer is shunted is

3663

ω

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111

ω

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107.7

ω

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3555.3

ω

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Solution

The correct option is D 3555.3 $ω$
Compensation external resistance
$G - \frac{S G}{S + G} = 3663 - 107.7 = 3555.3 ω$

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The correct option is D 3555.3 ωCompensation external resistanceG−SGS+G=3663−107.7=3555.3ω

The correct option is D 3555.3 $ω$
Compensation external resistance
$G - \frac{S G}{S + G} = 3663 - 107.7 = 3555.3 ω$