Question

A galvanometer of resistance $5\Omega$ has a scale divided into 100 equal divisions and has a current sensitivity of 10 divisions per milliampere. To convert it into an ammeter of range of 5 amp, the necessary shunt required is

• A. $5\Omega$
• B. $5\times 499\Omega$
• C. $\frac{5}{499}\Omega$
• D. $\frac{5}{500}\Omega$

Answer 1

The correct option is C $\frac{5}{499}\Omega$

$S=\frac{G}{\frac{I}{I_g}-1}S=\frac{5}{\frac{5}{10\times {10}^{-3}}-1}=\frac{5}{500-1}=\frac{5}{499}\Omega$