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Question

A gardener pushes a lawn roller through a distance 20m. If he applies a force of 20kg-wt in a direction inclined at 60o to the ground, the work done by him is


A

1960 J

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B

196 J

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C

1.96 J

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D

196 KJ

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Solution

The correct option is A

1960 J


Step1: Given data

A gardener pushes a lawn roller through a distance S=20m. If he applies a force of 20kg-wt in a direction inclined at θ=60o to the ground.

Step2: Formula used

W=FScosθ[whereW=workdone,F=constantforceapplied,S=dispalcement,θ=anglebetweenFandS]

Step3: Calculating the work done

Let us write down the given data, force applied by the gardener to push the lawn roller,
F=20kg-wt1kg-wt=9.8N

Therefore,
F=20kg-wtF=20×9.8NF=196N

Displacement of the lawn roller, S=20m

The angle between the direction of force applied and direction of displacement is, θ=60o

As the force applied by the gardener is constant, we can use the formula, W=FScosθ to find out the work done by the gardener.
Substituting F=196N,S=20m,andθ=60o in the formula we get,
W=196×20×cos60W=196×20×12Ascos60=12W=1960J

The work done by the gardener in pushing the lawn roller is 1960J.

Hence, option A is the correct answer.


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