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Question
A gas absorbs 120 J of heat and expands against the external pressure of 1.10 atm from a volume of 0.5 L to 2.0 L. What is the change in internal energy ? (1 atm = 101.3 J)
A gas absorbs 120 J of heat and expands against the external pressure of 1.10 atm from a volume of 0.5 L to 2.0 L. What is the change in internal energy ? (1 atm = 101.3 J)
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Solution
The correct option is A -47.1 J
Work of expansion,
w=−p△V△V=2.0−0.5=1.5L,p=1.10atmw=−1.10×1.5=−1.650 L−atm=−1.650×101.3(1 L−atm=101.3J)=−167.1 J
Since work is done by the system W = - 167.1 J
Heat absorbed by the system = 120 J or q = + 120 J
Now, △U=q+W=120J+(−167.1)=−47.1 J
Work of expansion,
w=−p△V△V=2.0−0.5=1.5L,p=1.10atmw=−1.10×1.5=−1.650 L−atm=−1.650×101.3(1 L−atm=101.3J)=−167.1 J
Since work is done by the system W = - 167.1 J
Heat absorbed by the system = 120 J or q = + 120 J
Now, △U=q+W=120J+(−167.1)=−47.1 J
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