1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard IX
Chemistry
Atoms
A gas at STP ...
Question
A gas at STP that contains
6.02
×
10
23
atoms and forms diatomic molecules will occupy :
A
11.2 L
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
22.4 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
33.6 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
67.2 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
1.06 quarts
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
11.2 L
6.02
×
10
23
atoms
=
1 mole
Number of moles of a diatomic molecule
=
1
/
2
mole
Total volume occupied
=
22.4
×
0.5
=
11.2
L
Suggest Corrections
0
Similar questions
Q.
At STP, a gas that contains
6.02
×
10
23
atoms and it forms diatomic molecules will occupy
:
Q.
500 ml of
N
H
3
contains
6.02
×
10
23
molecule at STP. How many molecules are present in 100 ml of
C
O
2
at STP?
Q.
The mass of
6.02
×
10
23
molecules of a gas is 64.0 grams. What volume does 8.00 grams of the gas occupy at standard temperature and pressure?
Q.
Ratio of
C
p
and
C
v
of a gas X is 1.4, the number of atom of the gas 'X' present in 11.2 litres of it at NTP will be
(1)
6.02
×
10
23
(2)
1.2
×
10
23
(3)
3.01
×
10
23
(4)
2.01
×
10
23
Q.
1 mole =
6.02
×
10
23
atoms and 1 mole =
6.02
×
10
23
,
molecules. How can molecules and atoms be equal?
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Atoms_tackle
CHEMISTRY
Watch in App
Explore more
Atoms
Standard IX Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app