Question

A gas cylinder contains 14.2 Kg butane gas. it is consumption of energy in a family is 10000 KJ for cooking purposes how long this cylinder will be sufficient to supply. If the enthalpy of combustion of butane is 2658 KJ mol

Answer 1

Solution:-

Enthalpy of combustion of butane $=2658kJ/mol\left(\text{Given}\right)$

Molecular weight of butane $=58g/mol$

Amount of butane gas contained in a cylinder $=14.2kg=14200g$

Therefore,

Heat released during combustion of $58g$ of butane $=2658kJ$

Heat released during combustion of $14200g$ of butane $=\frac{2658}{58}\times 14200kJ$

Now,

$10000kJ$ of energy is consumed in one day.

Therefore,

No. of days require to consume $(\frac{2658}{58}\times 14200)kJ$ of energy $=\frac{1}{10000}\times \frac{2658}{58}\times 14200\approx 65\text{days}$

Hence the cylinder will be sufficient for $65$ days.