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Question

A gas cylinder has walls that can bear a maximum pressure of 1.0×106 Pa. It contains a gas at 8.0×105 Pa and 300 K. The cylinder is steadily heated. Neglecting any change in the volume, calculate the temperature at which the cylinder will break~


A

350 K

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B

325 K

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C

375 K

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D

365 K

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Solution

The correct option is C

375 K


Since for a fixed mass of gas at constant volume, P increases linearly with temperature T, and vice versa, the ratio (TP) will be a constant.

Initial pressure, P1=8.0×105 Pa,

Initial temperature, T1=300 K,

Breaking pressure, P2=100×105 Pa

Let the temperature at which the type reaches the breaking pressure, be T2. We can write -

(T2P2)=(T1P1)

T2=[P2×T1P1]=[10×105×3008×105]K

T2=375 K.


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