A gas expands $0.25 m^{3}$ at constant pressure $10^{3} N / m^{2}$ . The work done is

250 N

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250 W

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250 J

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2.5 erg

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Solution

The correct option is B 250 J
Work done in expansion of gas $= \int P d V = P Δ V$
$= 10^{3} \times 0.25 = 250 J$

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