Question

A gas expands 0.25 $m^3$ at constant pressure 10${}^{3}N/m^2,$ the work done is

• A. 2.5 ergs
• B. 250 J
• C. 0.24 J
• D. 300 J

Answer 1

The correct option is B 250 J

$\begin{array}{c}P={10}^{7}N/m^2\\ \Delta v=0.25\\ w=\rho \Delta v\\ ={10}^3\times \frac{25}{100}\\ =250J\end{array}$

$\therefore$ Option $B$ is correct .