A gas expands adiabatically from 1.0 L to 12.0 L against a constant pressure of 0.75 atm. The $△ U$ of the gas is

- 835.9 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

853.9 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

859.9 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 839.5 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A - 835.9 J
First law of thermodynamics $△ U = Q + W$
$Q = 0$ (adibatic expansion)
$s o, △ U = W$
$△ U = W = - p_{e x t} △ V = - (0.75 a t m) (12.0 L - 1.0 L)$
$= 8.25 L a t m$
$\equiv - (8.25 L a t m) (\frac{8.314 J}{0.082 L a t m}) = - 835.9 J$

Suggest Corrections

Similar questions

△ U

When a sample of gas expands from $4.0 L$ to $12.0 L$ against a constant pressure of $0.3$ atm, the work done is:

Δ U

T

1 a t m

1 l i t r e t o 3 l i t r e s

Join BYJU'S Learning Program