A gas expands by $0.5$ liter against a constant pressure of one atmosphere. then the work done in Joules is:

- 50.66

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- 100.5

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- 200

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- 10

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Solution

The correct option is A $- 50.66$ J
The Work done in a Thermodynamic System at constant pressure is:
$W =$ $- P$ $Δ$ $V$
So,
$W =$ $- 1 \times 0.5$ L atm

$W = - 1 \times 0.5 \times$ $(8.314 / 0.082) J$

$W = - 101.325 \times 0.5$

$W = - 50.66$ J

Option A is correct.

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A gas expands by 0.5 liter against a constant pressure of one atmosphere. then the work done in Joules is:

The correct option is A −50.66 JThe Work done in a Thermodynamic System at constant pressure is:W= −P Δ VSo, W=−1×0.5 L atmW=−1×0.5× (8.314/0.082)J W=−101.325×0.5W=−50.66 JOption A is correct.

A gas expands by $0.5$ liter against a constant pressure of one atmosphere. then the work done in Joules is:

The correct option is A $- 50.66$ J
The Work done in a Thermodynamic System at constant pressure is:
$W =$ $- P$ $Δ$ $V$
So,
$W =$ $- 1 \times 0.5$ L atm

$W = - 1 \times 0.5 \times$ $(8.314 / 0.082) J$

$W = - 101.325 \times 0.5$

$W = - 50.66$ J

Option A is correct.