Question

A gas has a vapour density $11.2$. The volume occupied by $2.4g$ of the gas at STP will be:

• A. $11.2L$
• B. $2.4L$
• C. $1L$
• D. $10L$

Answer 1

Answer: (B)

$2.4L$

Number of moles $=\frac{Mass}{Molarmass}$
$=\frac{Mass}{2\times Vapourdensity}$

$=\frac{2.4}{2\times 11.2}=\frac{2.4}{22.4}$

Volume of gas $=n\times 22.4L$
$=\frac{2.4}{22.4}\times 22.4L=2.4L$