A gas has molecular formula $(C H)_{n}$ . If vapour density of the gas is 39, what should be the formula of the compound?

C_{3} H_{3}

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C_{4} H_{4}

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C_{2} H_{2}

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C_{6} H_{6}

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Solution

The correct option is D $C_{6} H_{6}$
Molecular formula= $(C H)_{n}$
molar mass $= (12 + 1) \times n = 13 n$
molar mass= $2 \times$ vapour density
$∴ 13 n = 2 \times 39$
$n = 6$
Compound is $(C H)_{6} = C_{6} H_{6}$

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