Question

A gas in a flexible container initially has volume of 320 L. If we decrease the pressure of the gas from 4.0 atm to 1.0 atm and decrease the temperature form 273 degrees Celsius to 0 degrees Celsius, what is the new volume of the gas?

• A. 0 L
• B. 320 L
• C. 160 L
• D. 640 L
• E. 80 L

Answer 1

Answer: (D)

640 L

Given : $V_1=320$ L , $P_1=4.0$ atm, $P_2=1.0$ atm

Initial temperature, $T_1={273}^{o}C=546$ K

Final temperature, $T_2=0^{o}C=273$ K

Using $\frac{P_2{V}_2}{T_2}=\frac{P_1{V}_1}{T_1}$

$\therefore$ $\frac{1.0\times V_2}{273}=\frac{4.0\times 320}{546}$ $⟹V_2=640$ L